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The bond length of H(2)^(+), H(2)^(-) "...

The bond length of ` H_(2)^(+), H_(2)^(-) " and "H_(2)` are in the order

A

`H_(2)^(+) gt H_(2) gt H_(2)^(-)`

B

`H_(2) gt H_(2)^(+) gt H_(2)^(-)`

C

`H_(2)^(-) gt H_(2) gt H_(2)^(+)`

D

`H_(2)^(-) gt H_(2)^(+) gt H_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the bond lengths of \( H_2^+, H_2^-, \) and \( H_2 \), we will follow these steps: ### Step 1: Understand the Concept of Bond Order Bond order is defined as the number of bonding pairs of electrons between two atoms. It can be calculated using the formula: \[ \text{Bond Order} = \frac{1}{2} \times (\text{Number of electrons in bonding MOs} - \text{Number of electrons in anti-bonding MOs}) \] Higher bond order indicates a stronger bond and a shorter bond length. ### Step 2: Determine the Molecular Orbital Configurations 1. **For \( H_2^+ \)**: - Total electrons = 1 (since \( H_2 \) has 2 electrons, and we remove one for \( H_2^+ \)). - Molecular orbital configuration: \( \sigma_{1s}^1 \) 2. **For \( H_2^- \)**: - Total electrons = 3 (adding one electron to \( H_2 \)). - Molecular orbital configuration: \( \sigma_{1s}^2 \sigma_{1s}^1 \) 3. **For \( H_2 \)**: - Total electrons = 2. - Molecular orbital configuration: \( \sigma_{1s}^2 \) ### Step 3: Calculate the Bond Order for Each Species 1. **For \( H_2^+ \)**: \[ \text{Bond Order} = \frac{1}{2} \times (1 - 0) = \frac{1}{2} \] 2. **For \( H_2^- \)**: \[ \text{Bond Order} = \frac{1}{2} \times (2 - 1) = \frac{1}{2} \] 3. **For \( H_2 \)**: \[ \text{Bond Order} = \frac{1}{2} \times (2 - 0) = 1 \] ### Step 4: Analyze the Bond Lengths Based on Bond Order - **Bond order and bond length relationship**: As bond order increases, bond length decreases. - \( H_2 \) has the highest bond order of 1, meaning it has the shortest bond length. - Both \( H_2^+ \) and \( H_2^- \) have a bond order of \( \frac{1}{2} \). However, \( H_2^- \) has an additional electron which leads to increased electron-electron repulsion, resulting in a longer bond length compared to \( H_2^+ \). ### Conclusion: Order of Bond Lengths Thus, the order of bond lengths from longest to shortest is: \[ H_2^- > H_2^+ > H_2 \]

To determine the bond lengths of \( H_2^+, H_2^-, \) and \( H_2 \), we will follow these steps: ### Step 1: Understand the Concept of Bond Order Bond order is defined as the number of bonding pairs of electrons between two atoms. It can be calculated using the formula: \[ \text{Bond Order} = \frac{1}{2} \times (\text{Number of electrons in bonding MOs} - \text{Number of electrons in anti-bonding MOs}) \] Higher bond order indicates a stronger bond and a shorter bond length. ...
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