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KCI crystallizes in the same type of lac...

`KCI` crystallizes in the same type of lacttice as does `NaCl`. Given that
`(r_(Na^(o+)))/(r_(Cl^(Θ))) = 0.5` and `(r_(Na^(o+)))/(r_(K^(o+))) = 0.7`
Calculate (a) the ratio of side of the unit cell for `KCl` to that for `NaCl`, and (b) the ratio of density of `NaCl` to that `KCl`.

A

`1.123`

B

`0.891`

C

`1.414`

D

`0.414`

Text Solution

Verified by Experts

The correct Answer is:
A
`(r_(Na^(+)))/(r_(Cl^(-)))=0.55 and (r_(k^(+)))/r_(Cl^(-))=0.74`
`(r_(Na^(+)))/(r_(Cl^(-)))+1=1.55 and (r_(k^(+)))/r_(Cl^(-))+1=1.74`
`(r_(Na^(+))+r_(Cl^(-)))/(r_(Cl^(-)))=1.55 and (r_(k^(+))+r_(cl^(-)))/r_(Cl^(-))=1.74`
`(r_(K^(+))+r_(Cl^(-)))/(r_(Na^(+))+r_(Cl^(-)))= (1.74)/(1.55)=1.123`
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