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If the radius of octaherdal void is 'r' ...

If the radius of octaherdal void is 'r' and radius of the atoms in close packing is 'R', then the relation between 'r' and 'R' is

A

`r = 0.414` R

B

`R = 0.414` r

C

`r = 2R`

D

`r = sqrt 2 R`

Text Solution

Verified by Experts

The correct Answer is:
A

`(2R)^(2) =(R+r)^(2)= (R+r)^(2)`
`sqrt(2R)= R+r`
`(sqrt(2)-1) R=r`
`0.414 R=r`
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