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The Delta H(0)(f) (KJ mol^(-1))" for "CO...

The `Delta H_(0)(f) (KJ mol^(-1))" for "CO_(2(g)), N_(2)O_((g)), CO_((g)) and NO_(2(g))` are -393, -10,81 and 34 respectively. What is the value of `Delta H (KJ mol^(-1))`, for the reaction ?
`2NO_(2(g))+3CO_((g)) rarr N_(2)O_((g))+3CO_(2(g))`

A

836

B

`-836`

C

1460

D

`-1660`

Text Solution

Verified by Experts

The correct Answer is:
D
`2NO_(2(g))+ 3CO_((g)) rarr N_(2)O_((g))+3CO_(2(g)) Delta H = ?`
`Delta H = Sigma H_(P)-Sigma H_(R)`
`=[2xxH_(N_(2)O(g))+3xxHCO_(2(g))]-[2xxH_(NO_(2(g)))+3xxH_(CO_(2(g)))]`
`Delta H =[-110+3xx-393]-[2xx34+3xx81]`
`Delta H =-1660 kJ`
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