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The heat of solution of anhydrous CuSO(4...

The heat of solution of anhydrous `CuSO_(4)` and `CuSO_(4).5H_(2)O` are -15.89 and 2.80 Kcal `mol^(-1)` respectively. What will be the heat of hydration of anhydrous `CuSO_(4)` ?

A

`-18.69 kcal`

B

`18.69 kcal`

C

`-28.96 kcal`

D

`28.96 kcal`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta H_("Hydration") = Delta H _("Anhydrous")CuSO_(4)-Delta H_("Hydrated") CuSO_(4)`
`=-15.89-2.80 =-18.69` kcal
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If the heat fo dissolution of anhydrous CuSO_(4) and CuSO_(4).5H_(2)O is -15.89 kcal and 2.80 kcal , respectively, then the heat of hydration fo CuSO_(4) to form CuSO_(4).5H_(2)O is

The enthalpies of solution of anhydrous CuSO_(4) and hydrated CuSO_(4). 5H_(2)O are -66.5 and 11.7 kJ mol^(-1) respectively.Calculate the enthalpy of hydration of CuSO_(4) to CuSO_(4).5H_(2)O .

In solid CuSO_(4).5H_(2)O

Heat of sol^(n) of CuSO_(4) (s) and CuSO_(4) . 5 H_(2) O is 15.9 and 19.3 kJ/mol respectively . Find the heat of hydration of CuSO_(4) (s)

CuSO_(4)*5H_(2)O belongs to

The heat of solution of anhydrous CuSO_(4) is -66.5 kJ and that of CuSO_(4).5H_(2)O is 11.7 kJ . Calculate is the heat of hydration of CuSO_(4) .

The integral enthalpies of solution of anhydrous CuSO_(4) (s) and hydrated CuSO_(4).5H_(2)O(s) are -70 kJ per mol and 10 kJ per mol respectively. Determine the magnitude of enthalpy of hydration of 0.1 mole anhydrous CuSO_(4) (s) as CuSO_(4)(s)+5H_(2)O(l)rarrCuSO_(4).5H_(2)O(s)

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