`10g` of argon gas is compressed isothermally and reversibly at a temperature of `27^(@)C` from `10L` to `5L`. Calculate `q, w, DeltaU`, and `DeltaH` for this process. `R = 2.0 cal K^(-1) "mol"^(-1), log_(10)2 = 0.30`. Atomic weight of `Ar = 40`.

Options

A. `W=106. 635 cal, q=103.635 cal, Delta U ne 0 and Delta H =0`
B. `W=53.635 cal, q=-53.635 cal, Delta U ne 0 and Delta H=0`
C. `w=-53.635 cal, q=63.635 cal, Delta U and Delta H ne 0`
D. `W=103.635 cal, q=-103.635 cal, Delta U and Delta H =0`

Answer

D

Explanation

Isothermal reversible process `Delta U and Delta H=0`.
q is -ve (compression)
`W=-2.303 nRT log _(10)(V_(2))/(V_(1))` (for compression W is + ve)
`=-2.303 xx(10)/(40) xx(273+27) log_(10) (5)/(10)`
`=2.303 xx300xx2xx0.301=103.6 cal`