For a particular reversible reaciton at temperature `T, DeltaH` and `DeltaS` were found to be both `+ve`. If `T_e` is the temperature at equilibrium, the reaciton would be spontaneous when :

Options

A. `T_(e) gt T`
B. `T gt T_(e)`
C. `T_(e)` is 5 times T
D. `T=T_(e)`

Answer

B

Explanation

`Delta G= Delta H- T Delta S`
At equilibrium, `Delta G=0`
For a reaction to be spontaneous `Delta G` should be negative.
`therefore T gt T_(e)`