The enthalpy of vaporisation of a liquid is `30 kJ mol^(-1)` and entropy of vaporisation is `75 J mol^(-1) K^(-1)`. The boiling point of the liquid at `1atm` is :

Options

A. 250 K
B. 400 K
C. 450 K
D. 600 K

Answer

B

Explanation

`dS =(dq_("rev"))/(T)" or "75 =(30xx10^(3))/(T)" or "T=400 K`