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If det(adjA)=|A|^(2), then the order of ...

If `det(adjA)=|A|^(2),` then the order of matrix A is

A

`2xx2`

B

`3xx3`

C

`2xx3`

D

`3xx2`

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The correct Answer is:
To solve the problem, we need to determine the order of the matrix \( A \) given that \( \text{det}(\text{adj} A) = |A|^2 \). ### Step-by-Step Solution: 1. **Understanding the Given Information**: We know that the determinant of the adjoint of a matrix \( A \) is related to the determinant of \( A \) itself. The formula for the determinant of the adjoint of a matrix is: \[ \text{det}(\text{adj} A) = |A|^{n-1} \] where \( n \) is the order of the matrix \( A \). 2. **Setting Up the Equation**: According to the problem, we have: \[ \text{det}(\text{adj} A) = |A|^2 \] From the formula, we can substitute: \[ |A|^{n-1} = |A|^2 \] 3. **Comparing the Exponents**: Since the determinants are equal, we can compare the exponents of \( |A| \): \[ n - 1 = 2 \] 4. **Solving for \( n \)**: To find \( n \), we solve the equation: \[ n - 1 = 2 \implies n = 2 + 1 = 3 \] 5. **Conclusion**: Therefore, the order of the matrix \( A \) is \( 3 \). This means that \( A \) is a \( 3 \times 3 \) matrix. ### Final Answer: The order of matrix \( A \) is \( 3 \) (or \( 3 \times 3 \)). ---
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MARVEL PUBLICATION-MATRICES-TEST YOUR GRASP
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