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`ABC` is triangle, right angled at A. The resultant of the forces acting along `vec(AB). vec(AC)` with magnitudes `1/(AB)` and respectively is the force along `vec(AD),` where D is the foot of the perpendicular from A onto BC. The magnitude of the resultant is-

A

`((AB)(AC))/(AB+BC)`

B

`1/(AB)+1/(AC)`

C

`1/(AD)`

D

`((AB)^(2)+(AC)^(2))/((AB)^(2).(AC)^(2))`

Text Solution

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The correct Answer is:
C
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