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bar(OA)=bara,bar(OB)=barb,bar(OC)=barc ...

`bar(OA)=bara,bar(OB)=barb,bar(OC)=barc`
then volume of the parallelopiped is :

A

`bara.(barbxxbarc)`

B

`(bara.barb)xxbarc`

C

`baraxxbarbxxbarc`

D

`bara(barb.barc)`

Text Solution

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The correct Answer is:
A
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