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A block placed on a rough harizontal sur...

A block placed on a rough harizontal surface is imparted a velocity of 10 m/s. the coefficient of kinetic friction between the block and the surface is 0.5 and g=`10m//s^2`. How much distance the block will cover, before coming to rest?

A

5 m

B

7.5 m

C

12 m

D

10 m

Text Solution

Verified by Experts

The correct Answer is:
D
The frictional force F`=muR=mumg` opposes the motion of the body.
`:.` The retardation a `=F/m=(mumg)/(m)=mug`
`:.` Using `v^2=u^2+`2as, we get
`:." "0=u^2+2(-mg)xxs`
`:." "2mugs=u^2`
`:." "s=(u^2)/(2mug)=(10xx10)/(2xx1/2xx10)=10m`
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