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A ball of mass 500 gram strikes a wall w...

A ball of mass 500 gram strikes a wall with a velocity of 80 m/s and rebounds with the same velocity. If the tme of contact is 1/30 sec, then the force exerted by the ball on the wall is

A

2000 N

B

2200 N

C

2400 N

D

2500 N

Text Solution

Verified by Experts

The correct Answer is:
C
Change is momentum (dP) = mv - (-mv) = 2 mv
`therefore dP = 2 xx (1)/(2) xx 80 = 80 kg kg m//s`
` therefore F = (dP)/(dt) = (80)/(1//30) = 2400 N`
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