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A rectangular block of mass 6 kg is to b...

A rectangular block of mass 6 kg is to be held against a rough vertical wall by appplying a force perpendicular to the wall. What is the minimum force to be applied, if the coefficient of friction is 0.42?

A

140 N

B

120 N

C

100 N

D

80 N

Text Solution

Verified by Experts

The correct Answer is:
A

Let P be the minimum force required to prevent the block from sliding down. For the equilibrium of the block, P=R and Mg=Force fo friction `F_s`)
`mu_s=(F_s)/R=(Mg)/P`
`:." "P=(Mg)/(mu_s)=(6xx9.8)/(0.42)=140N`
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