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A block of 5 kg is resting on a horizont...

A block of 5 kg is resting on a horizontal surface. The coefficient of kinetic friction between the block and the surface is 0.2. What is the acceleration with which the block will remove if a force of 9.8 N is applied to it ?

A

`2m//s^(2)`

B

`3m//s^(2)`

C

`1.5m//s^(2)`

D

`2.5m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Frictional force`=F=muR=mug`
`=0.2xx5xx9.8=9.8N`
When the forece of 19.8 N is applied, the
Effective force=Applied force-Force of friction
`=19.8-9.8=10N`
`:." "a=F/m=(10)/5=2m//s^2`
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