Home
Class 11
PHYSICS
A block weighing 10 kg just starts slidi...

A block weighing 10 kg just starts sliding down a rough inclined plane, which rises 5 in every 13 . What is the coefficient of friction ?

A

0.325

B

0.515

C

0.416

D

0.632

Text Solution

Verified by Experts

The correct Answer is:
C


Since the block just beigns to slide down the rough inclined plane,the angle of inclination `theta` is the angle of repose.
`:." "tantheta=mu`
In this case, `sintheta=5/(13),costheta=(12)/(13)` and `tantheta=5/(12)`
`:." "mu=tantheta=5/(12)=0.416`
Promotional Banner

Topper's Solved these Questions

  • FRICTIONAL IN SOLIDS AND LIQUIDS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|10 Videos
  • FORCE, WORK AND TORQUE

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|10 Videos
  • MAGNETIC EFFECT OF ELECTRIC CURRENT

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|10 Videos

Similar Questions

Explore conceptually related problems

A body weighing 20 kg just slides down a rough inclined plane that rises 5 m in every 13 m. What is the coefficient of friction?

A body weighing 20 kg just slides down a rough inclined plane that rises 5 in 12. The coefficient of friction is

A block of mass 1 kg is resting on a rough inclined plane which rises·3 in every 5. What is the minimum force required to move the block up the inclined plane ifµ == 0.5? (g =10m//s^2 )

A block is at rest at the top of a rough inclined plane of inclination 30° with the horizontal. What is the coefficient of kinetic friction between the block and the plane, if the . block slides down with an acceleration of g/5 ?

A block is released from the top of an inclined plane of inclination theta . Its velocity at the bottom of plane is v . If it slides down a rough inclined plane of the same inclination , its velocity at bottom is v//2 . The coefficient of friction is

A block of mass m is placed on a rough inclined plane of inclination theta kept on the floor of the lift. The coefficient of friction between the block and the inclined plane is mu . With what acceleration will the block slide down the inclined plane when the lift falls freely ?

A block of mass m slides down an inclined plane which makes an angle theta with the horizontal. The coefficient of friction between the block and the plane is mu . The force exerted by the block on the plane is

A block of mass 5 kg slides down a rough inclined surface. The angle of inclination is 45^(@) . The coefficient of sliding friction is 0.20. When the block slides 10 cm, the work done on the block by force of friction is

A block takes a twice as much time to slide down a 45^(@) rough inclined plane as it takes to slide down a similar smooth , plane . The coefficient of friction is :