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In a hydraulic press the small cylinder ...

In a hydraulic press the small cylinder has a diameter of `'d_1' cm`, while the large piston has a diameter of `'d_2' cm`. If a force `'F_1'` is applied to a small piston, the force on the large piston `'F_2'` is given by.

A

`F_2=(d_2^2)/(d_1^2)F_1`

B

`F_2=(d_2^2)/(d_1^2)(1_1)/(F_1)`

C

`F_2=(d_1^2)/(d_2^2)F_1`

D

`F_2=(d_1^2)/(d_2^2)(1_1)/(F_1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Hydraulic press is based upon Pascal's law.
As the pressure is transmitted undiminished in all direction, `P=(F_1)/(A_1)=(F_2)/(A_2)`
`:." "(F_2)/(F_1)=(A_2)/(A_1)=(pid_2^2)/(4)xx4/(pid_1^2)`
`:." "F_2=F_1((d_2^2)/(d_1^2))`
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