A rectangular glass vessel measuring `25 cmxx12 cmxx20` cm contains water of height 8 cm. Wh at is the thrust on the base of the vessel ?
[Density of water`=1000 kg//m^3,g=10m//s^2`]

Options

A. 24 N
B. 20 N
C. 16 N
D. 10 N

Explanation

To find the thrust on the base of the rectangular glass vessel containing water, we need to follow these steps:

### Step 1: Calculate the Area of the Base of the Vessel
The base of the vessel is rectangular, and its dimensions are given as:
- Length = 25 cm
- Width = 12 cm

To calculate the area (A) of the base:
\[ A = \text{Length} \times \text{Width} \]
Convert the dimensions from centimeters to meters:
- Length = 25 cm = 0.25 m
- Width = 12 cm = 0.12 m

Now, calculate the area:
\[ A = 0.25 \, \text{m} \times 0.12 \, \text{m} = 0.03 \, \text{m}^2 \]

### Step 2: Calculate the Pressure at the Bottom of the Vessel
The pressure (P) at the bottom of the vessel due to the water can be calculated using the formula:
\[ P = \rho \cdot g \cdot h \]
Where:
- \(\rho\) (density of water) = 1000 kg/m³
- \(g\) (acceleration due to gravity) = 10 m/s²
- \(h\) (height of water) = 8 cm = 0.08 m

Substituting the values:
\[ P = 1000 \, \text{kg/m}^3 \times 10 \, \text{m/s}^2 \times 0.08 \, \text{m} = 800 \, \text{N/m}^2 \]

### Step 3: Calculate the Thrust on the Base of the Vessel
The thrust (F) on the base of the vessel can be calculated using the formula:
\[ F = P \cdot A \]
Substituting the values of pressure and area:
\[ F = 800 \, \text{N/m}^2 \times 0.03 \, \text{m}^2 = 24 \, \text{N} \]

### Conclusion
The thrust on the base of the vessel is **24 N**.

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