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The dimensional formula for Reynold's nu...

The dimensional formula for Reynold's number is

A

`L^1M^1T^(-2)`

B

`L^0M^0T^(0)`

C

`L^(-1)M^2T^(-1)`

D

`L^1M^1T^(1)`

Text Solution

Verified by Experts

The correct Answer is:
D
Reynold's number is a dimensionless quantity. Its dimensional formula is `[L^0M^0T^0]`
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