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A metal plate of area 20 cm^2, is separa...

A metal plate of area 20 `cm^2`, is separated from a large plate by a layer of glycerine I mm thick. The coefficient of Viscosity of the glycerine is 20 poise. What is the honz?ntal force required to keep the plate moving with a velocity of 2 cm/s?
[poise=`10^(-1)N-s//m^2`]

A

0.04 N

B

0.05 N

C

0.06 N

D

0.08 N

Text Solution

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The correct Answer is:
To solve the problem, we need to find the horizontal force required to keep a metal plate moving with a certain velocity while separated from a large plate by a layer of glycerine. We will use the formula derived from Newton's law of viscosity. ### Step-by-Step Solution: 1. **Identify the given values:** - Area of the plate, \( A = 20 \, \text{cm}^2 \) - Thickness of glycerine layer, \( d = 1 \, \text{mm} \) - Coefficient of viscosity, \( \mu = 20 \, \text{poise} \) - Velocity of the plate, \( v = 2 \, \text{cm/s} \) 2. **Convert the units to SI:** - Convert area from cm² to m²: \[ A = 20 \, \text{cm}^2 = 20 \times 10^{-4} \, \text{m}^2 = 2 \times 10^{-3} \, \text{m}^2 \] - Convert thickness from mm to m: \[ d = 1 \, \text{mm} = 1 \times 10^{-3} \, \text{m} \] - Convert velocity from cm/s to m/s: \[ v = 2 \, \text{cm/s} = 2 \times 10^{-2} \, \text{m/s} \] - Convert viscosity from poise to SI units (1 poise = \( 0.1 \, \text{N s/m}^2 \)): \[ \mu = 20 \, \text{poise} = 20 \times 0.1 \, \text{N s/m}^2 = 2 \, \text{N s/m}^2 \] 3. **Calculate the velocity gradient:** - The velocity gradient \( \frac{dU}{dY} \) is given by: \[ \frac{dU}{dY} = \frac{v - 0}{d} = \frac{2 \times 10^{-2} \, \text{m/s}}{1 \times 10^{-3} \, \text{m}} = 20 \, \text{s}^{-1} \] 4. **Apply Newton's law of viscosity:** - The formula for the tangential force \( F \) is: \[ F = \mu A \frac{dU}{dY} \] - Substituting the values: \[ F = (2 \, \text{N s/m}^2) \times (2 \times 10^{-3} \, \text{m}^2) \times (20 \, \text{s}^{-1}) \] 5. **Calculate the force:** \[ F = 2 \times 2 \times 20 \times 10^{-3} = 80 \times 10^{-3} \, \text{N} = 0.08 \, \text{N} \] ### Final Answer: The horizontal force required to keep the plate moving with a velocity of 2 cm/s is \( 0.08 \, \text{N} \). ---

To solve the problem, we need to find the horizontal force required to keep a metal plate moving with a certain velocity while separated from a large plate by a layer of glycerine. We will use the formula derived from Newton's law of viscosity. ### Step-by-Step Solution: 1. **Identify the given values:** - Area of the plate, \( A = 20 \, \text{cm}^2 \) - Thickness of glycerine layer, \( d = 1 \, \text{mm} \) - Coefficient of viscosity, \( \mu = 20 \, \text{poise} \) ...
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