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An object placed at 20 cm from a lens, f...

An object placed at 20 cm from a lens, forms an image on a screen placed 60 cm on the other side of the lens. What is the focal length and type of the lens ?

A

15 cm and convex lens

B

`-15` cm and concave lens

C

18 cm and convex lens

D

`-18` cm and concave lens

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use the lens formula, which is given by: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \] where: - \( f \) is the focal length of the lens, - \( v \) is the image distance, - \( u \) is the object distance. ### Step-by-Step Solution: 1. **Identify the Object and Image Distances**: - The object distance \( u \) is given as 20 cm. According to the sign convention, since the object is placed on the same side as the incoming light, we take \( u = -20 \) cm. - The image distance \( v \) is given as 60 cm. Since the image is formed on the opposite side of the lens, we take \( v = +60 \) cm. 2. **Substitute Values into the Lens Formula**: - Using the lens formula: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \] Substitute \( v = 60 \) cm and \( u = -20 \) cm: \[ \frac{1}{f} = \frac{1}{60} - \frac{1}{-20} \] 3. **Calculate Each Term**: - Calculate \( \frac{1}{60} \): \[ \frac{1}{60} = 0.01667 \] - Calculate \( \frac{1}{-20} \): \[ \frac{1}{-20} = -0.05 \] 4. **Combine the Terms**: - Now, combine the two fractions: \[ \frac{1}{f} = 0.01667 + 0.05 = 0.06667 \] 5. **Calculate the Focal Length**: - To find \( f \), take the reciprocal: \[ f = \frac{1}{0.06667} \approx 15 \text{ cm} \] 6. **Determine the Type of Lens**: - Since the focal length \( f \) is positive, this indicates that the lens is a **convex lens**. ### Final Answer: - The focal length of the lens is **15 cm** and the type of lens is **convex**.

To solve the problem, we will use the lens formula, which is given by: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \] where: - \( f \) is the focal length of the lens, ...
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