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The equation of displacement of a particle performing a S.H.M. is x=0.25 "sin" (200 t) metre. What is the maximum velocity of the particle ?

A

`200 m//s`

B

`100 m//s`

C

`50 m//s`

D

`25 m//s`

Text Solution

Verified by Experts

The correct Answer is:
C
x=0.25 "sin" (200 t) compare with `x = A "sin" omega t`
`therefore A=0.25 " and " omega =200`
`therefore` Max velocity `=omega A=200xx0.25=50 m//s`
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