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Two simple harmonic motions are represen...

Two simple harmonic motions are represented by `y_(1)= 10 "sin" omega t " and " y_(2) =15 "cos" omega t`. The phase difference between them is

A

Zero

B

`(pi)/(6)` radian

C

`(pi)/(4)` radian

D

`(pi)/(2)` radian

Text Solution

Verified by Experts

The correct Answer is:
D
`y_(1)=10 "sin" omega t " " y_(2)=15 "sin" [omega t+(pi)/(2)]`
`therefore` The phase diff. `=(pi)/(2)`
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