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When a mercury drop of radius R, breaks ...

When a mercury drop of radius R, breaks into n droplets of equal size, the radius (r ) of each droplet is

A

`r = R/n`

B

`r=R/(n^(1//3))`

C

`r=Rn^(1//3)`

D

`root3(R/n)`

Text Solution

Verified by Experts

The correct Answer is:
B
` 4/3 piR^(3) = n . (4pi)/3 r^(3)" " :. R^3 = nr^(3)`
` :. R = n^(1//3) r " " :. R = R/(n^(1//3))`
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