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The surface tension of a liquid is 5xx10...

The surface tension of a liquid is `5xx10^(-2)` N/m in SI system ,In system it is expressed as

A

`5xx10^(2)` dyne/cm

B

`5xx10^(5)` dyne/cm

C

`5xx10^(1)` dyne/cm

D

`5xx10^(4)` dyne/cm

Text Solution

Verified by Experts

The correct Answer is:
C

` 5xx 10^(-2)N//m = (5 xx 10^(-2)xx 10^(5)"dyne")/(10^(2)cm)=5 xx 10^(1)` dyne/cm
` :' 1 N = 10^(5)"dyne and 1 m = " 10^(2) ` cm
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