Home
Class 12
PHYSICS
The work done in increasing the size of ...

The work done in increasing the size of a soap film from 10 cm × 6 cm to 10 cm × 11 cm is `3 xx10^(-4)` joule . The surface tension of the film is

A

`1.5 xx10^(-2)`N/m

B

`2xx10^(-2)`N/m

C

`2.5 xx10^(-2)`N/m

D

`3xx10^(-2)`N/m

Text Solution

Verified by Experts

The correct Answer is:
D
`S.T = (dW)/(dA) = (3 xx 10^(-4))/(2[110 -60]xx 10^(-4)) = 3xx 10^(-2)` N/m
Promotional Banner

Topper's Solved these Questions

  • SURFACE TENSION

    MARVEL PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS . (STANDARD LEVEL)|55 Videos

  • SURFACE TENSION

    MARVEL PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS . (HIGHER LEVEL)|35 Videos

  • STATIONARY WAVES

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP-8|20 Videos

  • WAVE MOTION

    MARVEL PUBLICATION|Exercise Test your grasp|15 Videos

Similar Questions

Explore conceptually related problems

The workdone in increasing the size of a soap film from 10 cm xx 6 cm to 10 cm xx 11 cm is 3 xx 10^(-4)J. The surface tension of the film is

If work done in increasing the size of a soap film from 10 cm x 6 cm to 10 cm x 11 cm is 2xx10^(-4) J , then the surface tension is

The work done in increasing the size of a soap film from 10cmxx6cm to 10cmxx11cm is 3xx10^-4 Joule. The surface tension of the film is

If work done in increasing the size of a soap film from 10cmxx6cmxx to 10cmxx11xm is 2xx10^-4H , then the surface tension is

Work of 6.0xx10^(-4) N joule is required to the done in increasing the size of soap film form 10cmxx6cm to 10cmxx11cm . The surface tension of the film is (in N//m)

Assertion : if work done in increasing th size of a soap film from 10 cm xx 4 cm to 10cm xx8cm is 2xx10^(-4) J, then the surface tension is 5xx10^(-4)N m^(-1) Reason : work done = surface tension xx increase in area .

The work done in increasing the size of a rectangular soap film with dimensions 8 cm x 3.75 cm to 10 cm x 6 cm is 2 xx 10^(-4) J . The surface tension of the film in (N m^(-1)) is

The work done in increasing the size film with dimensions 8cm xx3.75xm to 10cmxx6cm is 2xx10^(-4)J . The surface tension of the film in (N)/(m) is

The work done in increasing the size of a rectangular soap film with dimensions 8cm times3.75cm to 10cm times6cm is 2times10^(-4)J .The surface tension of the film in N/m is

The work done in increasing the radius of a soap bubble from 4 cm to 5 cm is Joule (given surface tension of soap water to be 25xx10^(-3)N//m)