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If the surface tension of a liquid is 5 ...

If the surface tension of a liquid is 5 N/m then the surface energy of the liquid film on a ring of area 0.15 `m^(2)` is

A

`1.5`J

B

`3.0`J

C

`2.25`J

D

`0.75`J

Text Solution

Verified by Experts

The correct Answer is:
A

`S.T .(T) = (dW)/(DA) = (dE)/(dA) `
` :. dE = T xx dA`
As there are two free surfaces for the film , dA = 2 (area of the film )
` :. dE = 2TdA = 2xx 5 xx 0.15 =1.5` J
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