Home
Class 12
PHYSICS
What is the force required to separate t...

What is the force required to separate two glass plates of area ` 3 xx 10^(-2) m^(2)` with a film of water of thickness 0.07 mm between them ? (Surface tension of water `= 7 xx 10^(-2)` N/m )

A

50 N

B

60 N

C

20 N

D

80 N

Text Solution

Verified by Experts

The correct Answer is:
B

`T = W/A or E/A`
` :. W = F xx d = 2TA`
` :. F = (2TA)/d = (2 xx 7xx10^(-2)xx3xx10^(-2))/(0.07 xx10^(-3))`
` = 6xx10^(1) = 60` N
Promotional Banner

Topper's Solved these Questions

  • SURFACE TENSION

    MARVEL PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS . (STANDARD LEVEL)|55 Videos
  • SURFACE TENSION

    MARVEL PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS . (HIGHER LEVEL)|35 Videos
  • STATIONARY WAVES

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP-8|20 Videos
  • WAVE MOTION

    MARVEL PUBLICATION|Exercise Test your grasp|15 Videos

Similar Questions

Explore conceptually related problems

Calculate the force required to separate the galss plates of area 10^(-2)m^(2) with a film of water 0.05 mm thickness between them (surface tension of waer =70xx10^(-3)N//m) )

If water rises in a capillary tube upto 3 cm . What is the diameter of capillary tube (Surface tension of water = 7.2 xx 10^(-2) N//m )

When one end of the capillary is dipped in water, the height of water column is 'h' . The upward force of 105 dyne due to surface tension is balanced by the force due to the weight of water column . The inner circumference of the capillary is (Surface tension of water = 7 xx 10^(-2) N//m )

Find the depth at which an air bubble of radius 0.7 mm will remain in equilibrium in water . Given surface tension of water = 7.0 xx 10^(-2) N/m.

The minimum force required to separate a light glass plate of perimeter 5m from a water surface is (Given surface tension of water = 70 xx 10^(-3) N/m)

Work done is splitting a drop of water of 1 mm radius into 64 droplets is (surface tension of water =72xx10^(-3)j m^(2))

A thin liquid film of thickness 5 xx 10^(-5) m is formed between two glass plates of surface area 1 xx 10^(-2) m^(2) , If the surface tension of the liquid is 60 xx 10^(-2) n/m the force that is required to separate the glass plates is

What is the force required to take away a flat circular plate of radius 2 cm from the surface of water ? T = 70 xx10^(3)N//m ." Use " pi = 22/7

Surface area of a soap bubble is 1.3xx10^(-4) m^2 . The work done to doble the surface area will be ( Surface tension for soap solution = 3xx10^(-3) N//m )

What force must be applied to detach two wetted photographic plates (9 cm xx 12 cm) in size from each other without shifting them. The thickness of water between the plates is 0.05 mm. Surface tension of water is 0.073 N/m.