Water rises upto a height h in a capillary on the surface of earth in stationary condition. Value of h increases if this tube is taken

Options

A. in a lift going upward with acceleration
B. on the sum
C. in a gift gong downward with acceleration (a) where `a lt g`
D. on the poles

Answer

C

Explanation

`h = (2T)/(rrhog)`
Thus `h prop 1/g` i.e h will increases , if g is decreased .
This happens if the capillary tube apparatus is kept in a lift going downward with an acceleration ` a lt g`
The effective acceleration ` = g - a`