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Work done in forming a liquid drop of ra...

Work done in forming a liquid drop of radius R is `W_(1)` and that of radius 3R is `W_(2)`. The ratio of work done is

A

`1:3`

B

`3:1`

C

`1:9`

D

`9:1`

Text Solution

Verified by Experts

The correct Answer is:
C
`(W_(1))/(W_(2)) = (8piR^(2)xxT)/(8pi(3R)^(2)xxT) xx 1/9 `
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