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If the radius of a soap bubble is four t...

If the radius of a soap bubble is four times that of another, then the ratio of their pressures will be

A

`4:1`

B

`1:4`

C

`16:1`

D

`1:16`

Text Solution

Verified by Experts

The correct Answer is:
B
`R_(1) = 4R_(2)`
Excess pressure `Delta P = (4T)/R`
` :. (DeltaP_(1))/(DeltaP_(2)) = (4T)/(R_(1)) xx (R_(2))/(4T) =(R_(2))/(R_(1)) = (R_(2))/(4R_(2)) = 1/4 `
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