If the ratio of the amplitudes of two interfering wave is 4:3, then the ratio of the maximumum and minimum intensities in the interference pattern is

Options

A. `9:16`
B. `16:9`
C. `49:1`
D. `1:49`

Answer

C

Explanation

`A_(1)/A_(2)=(4)/(3)" "therefore A_(1)=(4)/(3)A_(2)`
`(I_("max"))/(I_("min"))=((A_(1)+A_(2))^(2))/((A_(1)-A_(2))^(2))=(49)/(1)`