Two light waves of amplitudes `A_(1)` and `A_(2)` superimpose with each other such that `A_(1) gt A_(2)`. The difference between maximum and minimum amplitudes is

Options

A. `A_(1)-A_(2)`
B. `2A_(2)`
C. `2A_(1)`
D. `A_(1)+A_(2)`

Answer

B

Explanation

The maximum amplitude`=A_(1)+A_(2)`
and the minimum amplitude`=A_(1)-A_(2)" "(because A_(1)gtA_(2))`
`therefore`Difference between the maximum and minimum amplitudes
`=(A_(1)+A_(2))-(A_(1)-A_(2))=2A_(2)`