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In Young's double slit experiment carried out with light of wavelength `lamda=`5000 Å, the distance between the slits is 0.2 mm and screen is 2.0 m away from the slits. The central maximum is at n=0. the third maximum will be formed at a distance x (from the central maxima) equal to

A

0.5 cm

B

1.67 cm

C

1.5 cm

D

5 cm

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To solve the problem of finding the distance of the third maximum from the central maximum in Young's double slit experiment, we can follow these steps: ### Step 1: Understand the parameters given - Wavelength of light, \( \lambda = 5000 \, \text{Å} = 5000 \times 10^{-10} \, \text{m} = 5 \times 10^{-7} \, \text{m} \) - Distance between the slits, \( d = 0.2 \, \text{mm} = 0.2 \times 10^{-3} \, \text{m} = 2 \times 10^{-4} \, \text{m} \) - Distance from the slits to the screen, \( D = 2.0 \, \text{m} \) ### Step 2: Use the formula for the position of the m-th maximum The position of the m-th maximum on the screen is given by the formula: \[ x_m = \frac{m \lambda D}{d} \] where: - \( x_m \) is the distance from the central maximum to the m-th maximum, - \( m \) is the order of the maximum (in this case, \( m = 3 \)), - \( \lambda \) is the wavelength, - \( D \) is the distance from the slits to the screen, - \( d \) is the distance between the slits. ### Step 3: Substitute the values into the formula Substituting the known values into the formula for the third maximum (\( m = 3 \)): \[ x_3 = \frac{3 \times (5 \times 10^{-7} \, \text{m}) \times (2 \, \text{m})}{2 \times 10^{-4} \, \text{m}} \] ### Step 4: Calculate the value Calculating the above expression: \[ x_3 = \frac{3 \times 5 \times 2 \times 10^{-7} \, \text{m}}{2 \times 10^{-4} \, \text{m}} = \frac{30 \times 10^{-7}}{2 \times 10^{-4}} = \frac{30}{2} \times 10^{-3} = 15 \times 10^{-3} \, \text{m} = 0.015 \, \text{m} \] ### Step 5: Convert to centimeters To convert meters to centimeters: \[ 0.015 \, \text{m} = 1.5 \, \text{cm} \] ### Final Answer The distance \( x \) from the central maximum to the third maximum is: \[ x = 1.5 \, \text{cm} \] ---

To solve the problem of finding the distance of the third maximum from the central maximum in Young's double slit experiment, we can follow these steps: ### Step 1: Understand the parameters given - Wavelength of light, \( \lambda = 5000 \, \text{Å} = 5000 \times 10^{-10} \, \text{m} = 5 \times 10^{-7} \, \text{m} \) - Distance between the slits, \( d = 0.2 \, \text{mm} = 0.2 \times 10^{-3} \, \text{m} = 2 \times 10^{-4} \, \text{m} \) - Distance from the slits to the screen, \( D = 2.0 \, \text{m} \) ### Step 2: Use the formula for the position of the m-th maximum ...
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