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Two waves of equal amplitude and frequency interfere each other. The ratio of intensity when the two waves arrive in phase to that when they arrive `90^@` out of phase is

A

`1:1`

B

`sqrt(2):1`

C

`4:1`

D

`2:1`

Text Solution

Verified by Experts

The correct Answer is:
D

When they arrive in phase, the resultannt amplitude=2a
for a phase difference of `pi/2,R=[a^(2)+a^(2)]^(1//2)=sqrt(2)a`
`therefore (I_(1))/(I_(2))=(4a^(2))/(2a^(2))=(2)/(1)`
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