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In Young's experiment d=1 m, D=1m, X=0.6...

In Young's experiment d=1 m, D=1m, X=0.6mm, then wavelength of light used is

A

4000 A.U.

B

4800 A.U.

C

5000 A.U.

D

6000 A.U.

Text Solution

Verified by Experts

The correct Answer is:
D
`lamda=(Xd)/(D)=(6xx10^(-4)xx10^(-3))/(1)=6000` Å
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