In a Young's double slit esperiment, the angular width of a fringe formed on a distant screen is `1^(@)` . The slit separation is 0.01 mm. The wavelength of the light is

Options

A. 0.174 `mum`
B. 0.174 Å
C. 0.174`xx10^(-4)m`
D. 0.174 mm

Answer

A

Explanation

`d=0.01mm=10^(-5)m and theta=1^(@)=(pi)/(180)` radian
Angularr fringe width width `theta=(X)/(D)=(lamdaD)/(dD)=(lamda)/(d)`
`therefore lamda=dxxtheta`
`=10^(-5)xx(pi)/(180)=(3.14)/(180)xx10^(-5)`
`therefore lamda=1.74xx10^(-7)m=0.174xx10^(-6)`m
`lamda=0.174mum`