In a Young's double slit experiment (slit distance d) monochromatic light of wavelength `lambda` is used and the figure pattern observed at a distance L from the slits. The angular position of the bright fringes are

Options

A. `0=sin^(-1)((Nlamda)/(d))`
B. `theta=sin^(-1)(((HN+(1)/(2))lamda)/(d))`
C. `theta=sin^(-1)((Nlamda)/(L))`
D. `theta=sin^(-1)(((N+(1)/(2))lamda)/(L))`

Answer

A

Explanation

The distance of the Nth bright hand from the central bright band is `X_(N)=(NlamdaD)/(d)`
and from the figure, `sintheta=(X_(N))/(D)=(NlamdaD)/(dD)`
`therefore sintheta=(Nlamda)/(d)`
Thus `theta=sin^(-1)((Nlamda)/(d))`