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In a biprism experiment, the distance (d...

In a biprism experiment, the distance (d) between the two sources is doubled and the distance between the slit and the eye piece is also doubled. Then the width of the fringe

A

is doubled

B

is halved

C

remains unchanged

D

is reduced to `1/3`

Text Solution

Verified by Experts

The correct Answer is:
C
`X_(1)=(lamdaD)/(d),X_(2)=(lamda*2D)/(2d)=(lamdaD)/(d)`
`therefore X_(1)=X_(2)`
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