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In a biprism experiment, the distance be...

In a biprism experiment, the distance between the two virtual sources is 0.1 mm and the screen is placed at 100 cm from the slits. If the wavelength of light used is 5000 Å, then the distance of the 4th bright band from the central bright band will be

A

2 cm

B

1.5 cm

C

1 cm

D

3 cm

Text Solution

Verified by Experts

The correct Answer is:
A
`X_(n)=(nlamdaD)/(d)=(4xx5xx10^(-7)xx1)/(10^(-4))=2cm`.
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