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In a Biprism experiment, the slit separa...

In a Biprism experiment, the slit separation is 1mm. Using monochromatic light of wavelength 5000 Å, an interference patternn is obtained on a screen. For changing the bond width by `2.5xx10^(-5)`m.

A

the screen is moved away from the slits by 10 cm

B

the screen is moved towards the slits by 10 cm

C

the screen is moved away or towards the slits by 5 cm

D

the screen is moved away or towards the slits by 10 cm

Text Solution

Verified by Experts

The correct Answer is:
C

`X=(lamdaD)/(d)" "therefore DeltaX=(lamda(DeltaD))/(d)`
`therefore DeltaD=(d(Deltax))/(lamda)`
`=(10^(-3)xx2.5xxx10^(-5))/(5xx10^(-7))=1/(20)m=5cm`
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