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Light of wavelength 5500 Å falls normall...

Light of wavelength 5500 Å falls normally on a slit of width `11xx10^(-7)m` and the franhofer diffraction patternn is received on a screen. What is the angular position of the first minimum?

A

`60^(@)`

B

`30^(@)`

C

`45^(@)`

D

`20^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B
`sintheta=(lamda)/(a)=(5.5xx10^(-7))/(11xx10^(-7))=1/2" "therefore theta=30^(@)`.
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