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Wavelength of light used in an optical i...

Wavelength of light used in an optical instrument are `lamda_(1)=4500` Å and `lamda_(2)=6000` Å. What is the ratio of the resolving powers corresponding to `lamda_(1) and lamda_(2)`?

A

`3/4`

B

`4/3`

C

`9/(16)`

D

`(16)/(9)`

Text Solution

Verified by Experts

The correct Answer is:
B
`R.P.prop(1)/(lamda)`
`therefore (R.P.(i))/(R.P.(ii))=(lamda_(2))/(lamda_(1))=(6000)/(4500)=4/3`
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