The diameter of human eye lens is `2 mm`. What should be the minimum separation between two points situated at `50 m` from eye, to resolve tham. Take wavelength of light `= 5000 Å`.

Options

A. 1.25 cm
B. 2.35 cm
C. 3.5 cm
D. 4.8 cm

Answer

A

Explanation

The limit of angular resolution `(theta)` of the eye is given by
`theta=("wavelength of light")/("diameter of the eye lens")=(lamda)/(d)`
and if y is the minimum distance of resolutions between two objects at a diameter D from the eye, then `theta=(y)/(D)`
`therefore (lamda)/(D)=(lamda)/(d)`
`therefore y=(lamdaD)/(d)=(5000xx10^(-10)xx50)/(2xx10^(-3))`
`therefore y=12.5xx10^(-3)m=1.25cm`.