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In Young's double slit experiment carrie...

In Young's double slit experiment carried out with wavelength `lamda=5000`Å, the distance between the slits is 0.2 mm and the screen is 2 m away from the slits. The central maxima is at n=0. the third maxima will be at a distance x (from central maxima) is equal to

A

0.5 cm

B

1.5 cm

C

5 cm

D

1.67 cm

Text Solution

Verified by Experts

The correct Answer is:
B
`X=(lamdaD)/(d)" "therefore x=3X=1.5cm`
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