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In a young's double slit experiment, one...

In a young's double slit experiment, one of the slits is covered by a glass sheet of thickness `2.5xx10^(-5)`m. Due to this, the position of the central bright fringe is shifted to position originally occupied by the 30th bright fringe. If `lamda=5000` Å, then the refractive index of glass is

A

1.45

B

1.5

C

1.6

D

1.65

Text Solution

Verified by Experts

The correct Answer is:
C

`X_(n)=30X=(30lamdaD)/(d) and X_(n)=(D)/(d)(n-1)t`
`therefore (30lamdaD)/(d)=(D)/(d)(n-1)t`
`(n-1)=(30lamda)/(t)=(30xx10^(-7)xx5)/(2.5xx10^(-5))`
`therefore (n-1)=0.6" "therefore n=1.6`
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