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In a biprism experiment, the distance be...

In a biprism experiment, the distance between the consecutive bright bands is 0.32 mm, when red light of wavelength 6400 Å is used. By how much would the band width change, if blue light of wavelenth 4800 Å is used, with the same setting?

A

0.02 mm

B

0.04 mm

C

0.06 mm

D

0.08 mm

Text Solution

Verified by Experts

The correct Answer is:
D

`(X_(R))/(X_(B))=(lamda_(a))/(lamda_(B))=(4)/(3)" "(0.32)/(X_(B))=(4)/(3)`
`therefore X_(B)=0.24mm` `therefore dX=0.32-0.24=0.08mm`
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