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Light of wavelength lambda is incident o...

Light of wavelength `lambda` is incident on a slit of width d and distance between screen and slit is D. Then width of maxima and width of slit will be equal if D is ––

A

`a^(2)/lamda`

B

`lamda/(2a^(2))`

C

`(a^(2))/(2lamda)`

D

`(2a)/(lamda^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
Width of the central maximum `=2x=(2lamdaD)/(a)=a`
`therefore D=(a^(2))/(2lamda)`.
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