In the given circuit diagram, in the steady state the current through the battery and the charge on the capacitor respectively are

Options

A. 2 A and `3muC`
B. 11 A and `3muC`
C. `(6)/(11)A and (12)/(7)muC`
D. zero ampere and `3muF`

Answer

B

Explanation

The resistances `1Omega,2Omega,3Omega` are in parallel
`therefore (1)/(R)=(1)/(1)+(1)/(2)+(1)/(3)=(11)/(6)" "therefore R=(6)/(11)Omega`

In the steady state, the capacitor is fully charged and no current flows through it.
`therefore `No current flows through the `4Omega` resistance
`therefore1=(E)/(R)=(6)/((6)/(11))=11A`
and `Q=CV=0.5xx10^(-6)xx6=3xx10^(-6)=3muC`