The total energy of eletcron in the ground state of hydrogen atom is `-13.6 eV`. The kinetic enegry of an electron in the first excited state is

Options

A. `-27.2 eV`
B. `-6.8eV`
C. `-3.4eV`
D. `-52.4eV`

Answer

C

Explanation

The first excited state corresponds to n =2
`therefore E_2 = (-13.6)/(2^2) = (-13.6)/(4) = -3.4 eV`